If $f(x) = x(\sqrt{x} - \sqrt{x + 1}),$ then

  • A
    $f(x)$ is continuous but non-differentiable at $x = 0$
  • B
    $f(x)$ is differentiable at $x = 0$
  • C
    $f(x)$ is not differentiable at $x = 0$
  • D
    None of these

Explore More

Similar Questions

Let $f:R \to R$ be a function defined by $f(x) = \text{Min}\{x + 1, |x| + 1\}$. Then which of the following is true?

$f(x) = ||x| - 1|$ is not differentiable at

The function $f(x) = \begin{cases} e^x + ax, & x < 0 \\ b(x - 1)^2, & x \geq 0 \end{cases}$ is differentiable at $x = 0$. Then

Define $f(x) = \begin{cases} x^2 + bx + c, & x < 1 \\ x, & x \geq 1 \end{cases}$. If $f(x)$ is differentiable at $x = 1$,then $(b - c)$ is equal to

The function which is continuous for all real values of $x$ and differentiable at $x = 0$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo