If $A$ and $B$ are events such that $P(A \cup B) = 3/4,$ $P(A \cap B) = 1/4,$ and $P(\bar{A}) = 2/3,$ then $P(\bar{A} \cap B)$ is

  • A
    $5/12$
  • B
    $3/8$
  • C
    $5/8$
  • D
    $1/4$

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