If r.m.s. velocity of a gas is V_{rms} = 1840 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for $r.m.s.$ velocity is given by $V_{rms} = \sqrt{\frac{3P}{\rho}}$.Rearranging the formula to solve for pressure $P$,we get $P = \fr

Vedclass · Accepted Answer

$1.01 	imes 10^5 \ N/m^2$

Vedclass · Answer

(C) The formula for $r.m.s.$ velocity is given by $V_{rms} = \sqrt{\frac{3P}{ho}}$.Rearranging the formula to solve for pressure $P$,we get $P = \frac{ho V_{rms}^2}{3}$.Substituting the given values: $ho = 8.99 	imes 10^{-2} \ kg/m^3$ and $V_{rms} = 1840 \ m/s$.$P = \frac{8.99 	imes 10^{-2} 	imes (1840)^2}{3}$.$P = \frac{8.99 	imes 10^{-2} 	imes 3385600}{3}$.$P = \frac{304365.44}{3} \approx 101455.14 \ N/m^2$.Rounding to the appropriate significant figures,$P \approx 1.01 	imes 10^5 \ N/m^2$.

If $r.m.s.$ velocity of a gas is $V_{rms} = 1840 \ m/s$ and its density $\rho = 8.99 \times 10^{-2} \ kg/m^3$,the pressure of the gas will be

Similar Questions

$A$ gas has volume $V$ and pressure $P$. The total translational kinetic energy of all the molecules of the gas is

Average kinetic energy of gas molecules does not depend on which factors?

Define temperature in view of kinetic energy of a gas.

An ideal gas occupies a volume of $2\, m^3$ at a pressure of $3\times10^6\, Pa$. The energy of the gas is

Helium and argon are placed in a flask at the same room temperature $(300 \ K)$. What is the ratio of the average kinetic energies (per molecule) of helium and argon?

Vedclass Test Series

Exam Paper Generator

Online Exam Module