If $V$ denotes the potential difference across the plates of a capacitor of capacitance $C$,the dimensions of $CV^2$ are

When an additional charge of $2 \text{ C}$ is given to a capacitor,the energy stored in it increases by $21 \%$. The original charge of the capacitor is: (in $\text{ C}$)

$A$ battery is used to charge a parallel plate capacitor until the potential difference between the plates becomes equal to the e.m.f. of the battery. The ratio of the energy stored in the capacitor to the work done by the battery will be

Consider a parallel plate capacitor of area $A$ (of each plate) and separation $d$ between the plates. If $E$ is the electric field and $\varepsilon_0$ is the permittivity of free space between the plates,then the potential energy stored in the capacitor is $:-$

The work done in placing a charge of $8 \times 10^{-18} \, C$ on a condenser of capacity $100 \, \mu F$ is:

The capacitance of a capacitor is $4 \times 10^{-6} \ F$ and it is charged to a potential difference of $100 \ V$. The energy required to completely discharge it is . . . . . . $J$.