If a ball is thrown vertically upwards and th | vedclass

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Question

(C) Given the displacement equation: $s = 22t - 11t^{2}$.To find the maximum height, we differentiate $s$ with respect to $t$ to find the velocity $v

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(C) Given the displacement equation: $s = 22t - 11t^{2}$.To find the maximum height, we differentiate $s$ with respect to $t$ to find the velocity $v = \frac{ds}{dt}$.$\frac{ds}{dt} = 22 - 22t$.At the maximum height, the velocity is zero, so $22 - 22t = 0$, which gives $t = 1 	ext{ s}$.Substituting $t = 1$ into the displacement equation:$s = 22(1) - 11(1)^{2} = 22 - 11 = 11 	ext{ units}$.Since the ball starts from $s=0$ and reaches a maximum height of $11 	ext{ units}$, the total distance travelled is $11 	ext{ units}$.

If a ball is thrown vertically upwards and the height $s$ reached in time $t$ is given by $s = 22t - 11t^{2}$, then the total distance travelled by the ball is (in $\text{ units}$)

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