If a centre-tap transformer is used with two | vedclass

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(C) In a centre-tap full-wave rectifier,the secondary winding of the transformer is divided into two equal halves by the centre tap.If the total secon

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$\frac{1}{2} V_s$

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(C) In a centre-tap full-wave rectifier,the secondary winding of the transformer is divided into two equal halves by the centre tap.If the total secondary voltage across the entire secondary winding is $V_s$,then the voltage across each half of the secondary winding is $\frac{V_s}{2}$.During the positive half-cycle,one diode conducts and the voltage across the load is the voltage across the top half of the secondary,which is $\frac{V_s}{2}$.During the negative half-cycle,the other diode conducts and the voltage across the load is the voltage across the bottom half of the secondary,which is also $\frac{V_s}{2}$.Therefore,the output voltage with respect to each diode is $\frac{1}{2} V_s$.

If a centre-tap transformer is used with two $p-n$ junction diodes for full-wave rectification,then the output voltage of the rectifier with respect to each diode is (secondary voltage of transformer $= V_s$)

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