If a double stranded DNA has 20; % of cytosin | vedclass

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(C) According to $Chargaff's$ rule,in a double-stranded $DNA$,the amount of adenine $(A)$ is equal to thymine $(T)$,and the amount of cytosine $(C)$ i

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$30$

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(C) According to $Chargaff's$ rule,in a double-stranded $DNA$,the amount of adenine $(A)$ is equal to thymine $(T)$,and the amount of cytosine $(C)$ is equal to guanine $(G)$.Given that cytosine $(C)$ = $20\; \%$,then guanine $(G)$ must also be $20\; \%$.The total percentage of $C + G = 20\; \% + 20\; \% = 40\; \%$.Since the total percentage of all four bases is $100\; \%$,the remaining percentage for adenine and thymine is $100\; \% - 40\; \% = 60\; \%$.Since $A = T$,the percentage of adenine is $60\; \% / 2 = 30\; \%$.

If a double stranded $DNA$ has $20\; \%$ of cytosine,what will be the percentage of adenine in it (in $; \%$)?

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