If a heat engine and a refrigerator are working between the same two temperatures $T_1$ and $T_2$ $(T_1 > T_2)$,then the ratio of the efficiency of the heat engine to the coefficient of performance of the refrigerator is:

  • A
    $\frac{T_1 - T_2}{T_1 T_2}$
  • B
    $\frac{T_1 + T_2}{T_1 T_2}$
  • C
    $\frac{(T_1 - T_2)^2}{T_1 T_2}$
  • D
    $\frac{(T_1 + T_2)^2}{T_1 T_2}$

Explore More

Similar Questions

An ideal monoatomic gas is taken through a process $dQ = 2dU$. The molar heat capacity for the process is:

An ideal gas expands from volume $V_1$ to $V_2$. This may be achieved by either of the three processes: isobaric,isothermal,and adiabatic. Let $\Delta U$ be the change in internal energy of the gas,$Q$ be the quantity of heat added to the system,and $W$ be the work done by the system. Identify which of the following statements is false for $\Delta U$?

What are the limitations of the first law of thermodynamics?

Difficult
View Solution

$A$ thermodynamic cycle of an ideal gas is shown in the figure. Choose the correct option which represents the same cycle.

What is an isothermal process, adiabatic process, and isobaric process? Write the first law of thermodynamics for an ideal gas.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo