If a length of DNA has 45,000 base pairs,how | vedclass

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(A) In a $B-DNA$ double helix,one complete turn consists of $10$ base pairs.To find the total number of complete turns,we divide the total number of b

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$4,500$

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(A) In a $B-DNA$ double helix,one complete turn consists of $10$ base pairs.To find the total number of complete turns,we divide the total number of base pairs by the number of base pairs per turn.Total base pairs = $45,000$.Base pairs per turn = $10$.Number of turns = $\frac{45,000}{10} = 4,500$.Therefore,the $DNA$ molecule will take $4,500$ complete turns.

If a length of $DNA$ has $45,000$ base pairs,how many complete turns will the $DNA$ molecule take?

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