If a man spends frac{5}{6} part of his money | vedclass

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(B) Let the initial amount of money with the man be $1$.$	herefore$ Money spent $= \frac{5}{6}$ of $1 = \frac{5}{6}$.$	herefore$ Remaining money $=

Vedclass · Accepted Answer

$\frac{1}{4}$

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(B) Let the initial amount of money with the man be $1$.$	herefore$ Money spent $= \frac{5}{6}$ of $1 = \frac{5}{6}$.$	herefore$ Remaining money $= 1 - \frac{5}{6} = \frac{1}{6}$.He earns $\frac{1}{2}$ of the remaining money,so money earned $= \frac{1}{2} 	imes \frac{1}{6} = \frac{1}{12}$.$	herefore$ Total money with him now $= 	ext{Remaining money} + 	ext{Money earned} = \frac{1}{6} + \frac{1}{12}$.To add these,find the common denominator,which is $12$: $\frac{2}{12} + \frac{1}{12} = \frac{3}{12} = \frac{1}{4}$.Thus,$\frac{1}{4}$ part of his money is with him now.

If a man spends $\frac{5}{6}$ part of his money and,again earns $\frac{1}{2}$ part of the remaining money,what part of his money is with him now?

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