(B) Let the distance to the station be $D\, km$ and the scheduled time of the train be $T\, hours$.Case $1$: When walking at $5\, km/h$,he is late by

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(B) Let the distance to the station be $D\, km$ and the scheduled time of the train be $T\, hours$.Case $1$: When walking at $5\, km/h$,he is late by $7\, minutes$ $(7/60\, hours)$.Time taken = $D/5 = T + 7/60$.Case $2$: When walking at $6\, km/h$,he reaches $5\, minutes$ $(5/60\, hours)$ early.Time taken = $D/6 = T - 5/60$.Subtracting the second equation from the first:$(D/5) - (D/6) = (T + 7/60) - (T - 5/60)$.$(6D - 5D) / 30 = 12/60$.$D/30 = 1/5$.$D = 30/5 = 6\, km$.Therefore,the distance to the station is $6\, km$.

Competitive Quantitative Aptitude Time and Distances Time and Distances

Medium

If a man walks at the rate of $5\, km/h$,he misses a train by $7\, minutes$. However,if he walks at the rate of $6\, km/h$,he reaches the station $5\, minutes$ before the arrival of the train. The distance covered by him to reach the station is (in $km$)

A
$4$
B
$6$
C
$6.25$
D
$7$

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Time and Distances

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Time and Distances

Two trains of equal length take $10 \, s$ and $15 \, s$ respectively to cross a telegraph post. If the length of each train is $120 \, m$,in what time (in $s$) will they cross each other while travelling in the same direction?

Easy

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Train $A$ crosses a stationary Train $B$ in $50 \text{ seconds}$ and a pole in $20 \text{ seconds}$ with the same speed. The length of Train $A$ is $240 \text{ meters}$. What is the length of the stationary Train $B$ (in meters)?

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$A$ train running at a speed of $60\, km/h$ crosses a platform double its length in $32.4\, seconds.$ What is the length of the platform? (in $m$)

Medium

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$A$ train is running at a uniform speed of $60 \, km/h$. It passes a railway platform in $15 \, s$. If the length of the platform is $130 \, m$,then the length of the train is (in $m$):

Medium

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$A$ $320\, m$ long train moving at an average speed of $120\, km/h$ crosses a platform in $24\, seconds$. $A$ man crosses the same platform in $4\, minutes$. What is the speed of the man in $m/s$?

Difficult

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If a man walks at the rate of $5\, km/h$,he misses a train by $7\, minutes$. However,if he walks at the rate of $6\, km/h$,he reaches the station $5\, minutes$ before the arrival of the train. The distance covered by him to reach the station is (in $km$)

Similar Questions

Two trains of equal length take $10 \, s$ and $15 \, s$ respectively to cross a telegraph post. If the length of each train is $120 \, m$,in what time (in $s$) will they cross each other while travelling in the same direction?

Train $A$ crosses a stationary Train $B$ in $50 \text{ seconds}$ and a pole in $20 \text{ seconds}$ with the same speed. The length of Train $A$ is $240 \text{ meters}$. What is the length of the stationary Train $B$ (in meters)?

$A$ train running at a speed of $60\, km/h$ crosses a platform double its length in $32.4\, seconds.$ What is the length of the platform? (in $m$)

$A$ train is running at a uniform speed of $60 \, km/h$. It passes a railway platform in $15 \, s$. If the length of the platform is $130 \, m$,then the length of the train is (in $m$):

$A$ $320\, m$ long train moving at an average speed of $120\, km/h$ crosses a platform in $24\, seconds$. $A$ man crosses the same platform in $4\, minutes$. What is the speed of the man in $m/s$?

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