If a number is reduced by 40 % it becomes two | vedclass

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(D) Let the first number be $a$ and the second number be $b$.According to the problem,reducing the first number by $40 \%$ gives $\frac{2}{3}$ of the

Vedclass · Accepted Answer

$9:10$

Vedclass · Answer

(D) Let the first number be $a$ and the second number be $b$.According to the problem,reducing the first number by $40 \%$ gives $\frac{2}{3}$ of the second number.$a - 0.40a = \frac{2}{3}b$$0.60a = \frac{2}{3}b$$\frac{60}{100}a = \frac{2}{3}b$$\frac{3}{5}a = \frac{2}{3}b$To find the ratio of the second number $(b)$ to the first number $(a)$,we rearrange the equation:$\frac{b}{a} = \frac{3}{5} 	imes \frac{3}{2} = \frac{9}{10}$Therefore,the ratio of the second number to the first number is $9:10$.

If a number is reduced by $40 \%$ it becomes two-thirds of another number. What is the ratio of the second number to the first number?

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