If a radioactive isotope with atomic number $A$ and mass number $M$ emits an $\alpha$-particle,the atomic number and mass number of that new isotope will become:

$A$ radioactive nuclide $X$ decays at the rate of $1.00 \times 10^5 \ disintegration \ s^{-1} \ g^{-1}$. Radium decays at the rate of $3.70 \times 10^{10} \ disintegration \ s^{-1} \ g^{-1}$. The activity of $X$ in millicuries $g^{-1}$ $(mCi \ g^{-1})$ is

Explain $\alpha$,$\beta$,and $\gamma$-rays.

When a radioactive nucleus emits an $\alpha$-particle,the mass of the atom

The $_{88}Ra^{226}$ is

$A$ radioactive atom $^X_Y M$ emits two $\alpha$ particles and one $\beta$ particle successively. The number of neutrons in the nucleus of the product will be