If a ray of light passes through an equilater | vedclass

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(D) For a prism, the relationship between the angles is given by $A + \delta = i + e$, where $A$ is the angle of the prism, $\delta$ is the angle of d

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(D) For a prism, the relationship between the angles is given by $A + \delta = i + e$, where $A$ is the angle of the prism, $\delta$ is the angle of deviation, $i$ is the angle of incidence, and $e$ is the angle of emergence.Given that the prism is equilateral, the angle of the prism $A = 60^{\circ}$.The angle of incidence $i$ and the angle of emergence $e$ are both equal to $70 \%$ of the angle of the prism.Therefore, $i = e = 0.70 	imes 60^{\circ} = 42^{\circ}$.Substituting these values into the formula $A + \delta = i + e$:$60^{\circ} + \delta = 42^{\circ} + 42^{\circ}$$60^{\circ} + \delta = 84^{\circ}$$\delta = 84^{\circ} - 60^{\circ} = 24^{\circ}$.Thus, the angle of deviation is $24^{\circ}$.

If a ray of light passes through an equilateral prism such that the angle of incidence and the angle of emergence are both equal to $70 \%$ of the angle of the prism, then the angle of deviation is (in $^{\circ}$)

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