If a root of the given equation a(b - c)x^2 + | vedclass

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(C) Given the quadratic equation $a(b - c)x^2 + b(c - a)x + c(a - b) = 0$.Let the roots be $\alpha$ and $\beta$. We are given that $\alpha = 1$.For a

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$\frac{c(a - b)}{a(b - c)}$

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(C) Given the quadratic equation $a(b - c)x^2 + b(c - a)x + c(a - b) = 0$.Let the roots be $\alpha$ and $\beta$. We are given that $\alpha = 1$.For a quadratic equation $Ax^2 + Bx + C = 0$,the product of roots is given by $\alpha \beta = \frac{C}{A}$.Here,$A = a(b - c)$,$B = b(c - a)$,and $C = c(a - b)$.Substituting the values,we get $1 	imes \beta = \frac{c(a - b)}{a(b - c)}$.Therefore,the other root $\beta = \frac{c(a - b)}{a(b - c)}$.

If a root of the given equation $a(b - c)x^2 + b(c - a)x + c(a - b) = 0$ is $1$,then the other root will be

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