If all the words,with or without meaning,are | vedclass

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Question

(C) The letters in the word $QUEEN$ are $E, E, N, Q, U$. Arranging them in alphabetical order: $E, E, N, Q, U$.$(i)$ Words starting with $E$: The rema

Vedclass · Accepted Answer

$46$

Vedclass · Answer

(C) The letters in the word $QUEEN$ are $E, E, N, Q, U$. Arranging them in alphabetical order: $E, E, N, Q, U$.$(i)$ Words starting with $E$: The remaining letters are $E, N, Q, U$ (all distinct). Number of words $= 4! = 24$.$(ii)$ Words starting with $N$: The remaining letters are $E, E, Q, U$. Number of words $= \frac{4!}{2!} = 12$.$(iii)$ Words starting with $QE$: The remaining letters are $E, N, U$. Number of words $= 3! = 6$.$(iv)$ Words starting with $QN$: The remaining letters are $E, E, U$. Number of words $= \frac{3!}{2!} = 3$.$(v)$ The next word is $QUEEN$ itself,which is the $1^{st}$ word after the above arrangements.Therefore,the rank of the word $QUEEN = 24 + 12 + 6 + 3 + 1 = 46^{th}$.

If all the words,with or without meaning,are written using the letters of the word $QUEEN$ and are arranged as in an English dictionary,then the position of the word $QUEEN$ is (in $^{th}$)

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