If an electron and a photon propagate in the form of waves having the same wavelength,it implies that they have the same

Find the de Broglie wavelength of an electron in a metal at $27^{\circ}C$.

The de-Broglie wavelength $\lambda$ associated with an electron having kinetic energy $E$ is given by the expression:

The wavelength of a probe is roughly a measure of the size of a structure that it can probe in some detail. The quark structure of protons and neutrons appears at the minute length-scale of $10^{-15} \;m$ or less. This structure was first probed in early $1970s$ using high energy electron beams produced by a linear accelerator at Stanford,$USA$. Guess what might have been the order of energy of these electron beams. (Rest mass energy of electron $= 0.511 \;MeV$.)

What is a wave packet?

The de Broglie wavelengths of a proton and an $\alpha$ particle are $\lambda$ and $2\lambda$ respectively. The ratio of the velocities of proton and $\alpha$ particle will be: