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(B) The work done on a charge $q$ moving between two points with a potential difference $\Delta V$ is given by $W = q \Delta V$.Since the electron sta

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$3.2 	imes 10^{-18} \, J$

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(B) The work done on a charge $q$ moving between two points with a potential difference $\Delta V$ is given by $W = q \Delta V$.Since the electron starts from rest,the work done by the electric field is equal to the change in its kinetic energy.The potential difference is $\Delta V = V_{final} - V_{initial} = 70\, V - 50\, V = 20\, V$.The charge of an electron is $q = 1.6 	imes 10^{-19} \, C$.Therefore,the kinetic energy $K.E. = q 	imes \Delta V = (1.6 	imes 10^{-19} \, C) 	imes (20 \, V) = 3.2 	imes 10^{-18} \, J$.

If an electron moves from rest from a point at which potential is $50\, V$ to another point at which potential is $70\, V$,then its kinetic energy in the final state will be:

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