If an electron revolves around a nucleus in a circular orbit of radius $R$ with frequency $n$,then the magnetic field produced at the centre of the nucleus will be

  • A
    $\frac{\mu_0 e n}{2 R}$
  • B
    $\frac{\mu_0 e n}{4 \pi R}$
  • C
    $\frac{4 \pi \mu_0 e n}{R}$
  • D
    $\frac{4 \pi \mu_0 e}{R n}$

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What is the magnetic field at a distance $R$ from a coil of radius $r$ carrying current $I$ along its axis?

$A$ current $i$ is flowing through the loop. The direction of the current and the shape of the loop are as shown in the figure. The magnetic field at the centre $M$ of the loop is $\frac{\mu_{0} i}{R}$ times
$(MA=R, MB=2 R, \angle DMA=90^{\circ})$

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