If an ideal gas is compressed isothermally, w | vedclass

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(D) For an ideal gas, the internal energy $U$ is a function of temperature $T$ only $(U = f(T))$.In an isothermal process, the temperature $T$ remains

Vedclass · Accepted Answer

The internal energy of the gas remains constant.

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(D) For an ideal gas, the internal energy $U$ is a function of temperature $T$ only $(U = f(T))$.In an isothermal process, the temperature $T$ remains constant $(\Delta T = 0)$.Therefore, the change in internal energy $\Delta U$ is zero.According to the first law of thermodynamics, $Q = \Delta U + W$, where $Q$ is the heat added to the system and $W$ is the work done by the system.Since $\Delta U = 0$, we have $Q = W$.When a gas is compressed, work is done on the gas $(W Since the temperature is constant, the internal energy remains constant.

If an ideal gas is compressed isothermally, which of the following statements is true?

Similar Questions

Which of the following,in general,is a slow process?

If an ideal gas is compressed isothermally,then:

$A$ certain gas is isothermally compressed to $(1/3)^{rd}$ of its initial volume $(V_0 = 3 \ \text{L})$ by applying required pressure. If the bulk modulus of the gas is $3 \times 10^5 \ \text{N/m}^2$, the magnitude of work done on the gas is . . . . . . $J$.

For an ideal gas, in an isothermal process:

Write the first law of thermodynamics for an isothermal process in an ideal gas.

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