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(C) According to Gauss's Law,the electric flux through a Gaussian surface is given by $\oint E \cdot dA = \frac{q_{enc}}{\varepsilon_0}$.For a non-con

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$\frac{\rho r}{3\varepsilon_0}$

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(C) According to Gauss's Law,the electric flux through a Gaussian surface is given by $\oint E \cdot dA = \frac{q_{enc}}{\varepsilon_0}$.For a non-conducting sphere with uniform charge density $ho$,the charge enclosed $q_{enc}$ within a sphere of radius $r$ $(r Applying Gauss's Law for a spherical Gaussian surface of radius $r$:$E 	imes (4 \pi r^2) = \frac{ho 	imes (\frac{4}{3} \pi r^3)}{\varepsilon_0}$.Simplifying the equation:$E = \frac{ho 	imes \frac{4}{3} \pi r^3}{4 \pi r^2 \varepsilon_0}$.$E = \frac{ho r}{3\varepsilon_0}$.

If an insulated non-conducting sphere of radius $R$ has charge density $\rho$,the electric field at a distance $r$ from the centre of the sphere $(r < R)$ will be

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