If both the object and the image are at infin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For a refracting telescope,the magnifying power $(m)$ is defined as the ratio of the angle subtended by the image at the eye to the angle subtende

Vedclass · Accepted Answer

The ratio of the focal length of the objective and the eyepiece

Vedclass · Answer

(C) For a refracting telescope,the magnifying power $(m)$ is defined as the ratio of the angle subtended by the image at the eye to the angle subtended by the object at the objective.When the object is at infinity,the image formed by the objective lens is at its focal plane $(f_o)$.When the final image is also at infinity (normal adjustment),the eyepiece is positioned such that the image formed by the objective lies at the focal point of the eyepiece $(f_e)$.In this configuration,the magnifying power is given by the formula $m = \frac{f_o}{f_e}$,where $f_o$ is the focal length of the objective lens and $f_e$ is the focal length of the eyepiece.

If both the object and the image are at infinite distances from a refracting telescope,its magnifying power will be equal to:

Similar Questions

The magnifying power of an astronomical telescope is $8$. If the distance between the two lenses is $54 \, cm$,find the focal lengths of the eyepiece and the objective lens.

The magnifying power of a telescope is high if its objective and eyepiece have respectively

If a telescope is reversed,i.e.,viewed from the objective side,what happens to the appearance of the object?

When a telescope is adjusted for parallel light,the distance of the objective from the eyepiece is found to be $80 \,cm$. The magnifying power of the telescope is $19$. The focal lengths of the lenses are

Vedclass Test Series

Exam Paper Generator

Online Exam Module