If an electron,hydrogen nucleus,helium nucleus,and neon nucleus are all moving with the same velocity,then the wavelengths associated with these particles are in the order:
- A$Electron > Hydrogen > Helium > Neon$
- B$Electron > Helium > Hydrogen > Neon$
- C$Electron < Hydrogen < Helium < Neon$
- D$Neon < Hydrogen < Helium < Electron$
Explore More
Similar Questions
If the kinetic energy of an electron of mass $9.0 \times 10^{-31} \ kg$ is $8.0 \times 10^{-25} \ J$,the wavelength of this electron in $nm$ is
If the wavelength of a photon is $2.2 \times 10^{-11} \ m$ and $h = 6.6 \times 10^{-34} \ J \ s$,then the momentum of the photon is:
MediumKCET 2022
View SolutionThe de-Broglie equation is:
Easy
View SolutionThe wavelength associated with an electron moving with a velocity of $10^8 \, cm/s$ is ........ $\mathop {\rm{A}}\limits^{\rm{o}} $.
Medium
View SolutionWhat is the de-Broglie wavelength associated with the hydrogen electron in its third orbit?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo