If five-digit numbers are formed from the dig | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The total number of five-digit numbers formed using the digits $0, 1, 2, 3, 4$ exactly once is $4 	imes 4! = 4 	imes 24 = 96$. For a number to b

Vedclass · Accepted Answer

$\frac{5}{16}$

Vedclass · Answer

(A) The total number of five-digit numbers formed using the digits $0, 1, 2, 3, 4$ exactly once is $4 	imes 4! = 4 	imes 24 = 96$. For a number to be divisible by $4$,the last two digits must form a number divisible by $4$. The possible pairs for the last two digits are: $04, 20, 40$ (where $0$ is used): Each gives $3! = 6$ numbers. Total $= 3 	imes 6 = 18$. $12, 24, 32$ (where $0$ is not used): For each,the first digit cannot be $0$,so there are $3$ choices for the first digit and $2!$ for the remaining two. Total $= 3 	imes (3 	imes 2!) = 3 	imes 6 = 18$. Wait,let us re-evaluate: If last two digits are $04, 20, 40$: The remaining $3$ digits can be arranged in $3! = 6$ ways. $3 	imes 6 = 18$. If last two digits are $12, 24, 32$: The first digit cannot be $0$ and cannot be one of the two digits used. So $4 - 2 = 2$ choices for the first digit,then $2!$ for the remaining. $3 	imes (2 	imes 2!) = 3 	imes 4 = 12$. Total favorable numbers $= 18 + 12 = 30$. Probability $= \frac{30}{96} = \frac{5}{16}$.

If five-digit numbers are formed from the digits $0, 1, 2, 3, 4$ using every digit exactly once,then the probability that a randomly chosen number from those numbers is divisible by $4$ is:

Similar Questions

$A$ total of $13$ people,consisting of $5$ women and $8$ men,have applied for a job. If $2$ people are to be selected from these $13$ people,what is the probability that at least one woman is selected?

From a well-shuffled pack of $52$ cards,two cards are drawn at random. The probability that both cards are kings is:

$A$ class has $15$ boys and $5$ girls. Suppose $3$ students are selected at random from the class. The probability that there are $2$ boys and $1$ girl is

Two cards are drawn at random from a pack of $52$ cards. The probability of these two being Aces is

Out of the first $5$ consecutive natural numbers,if two different numbers $x$ and $y$ are chosen at random,then the probability that $x^4 - y^4$ is divisible by $5$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module