If force $\overrightarrow F = 4\hat i + 5\hat j$ and displacement $\overrightarrow s = 3\hat i + 6\hat k$, then the work done is: (in $\text{ J}$)

$A$ body of mass $m$ accelerates uniformly from rest to a speed $v_0$ in time $t_0$. The work done on the body till any time $t$ is

$A$ force of $(4 \hat{i}+2 \hat{j}+\hat{k}) \text{ N}$ is acting on a particle of mass $2 \text{ kg}$,displacing the particle from a position of $(2 \hat{i}+2 \hat{j}+\hat{k}) \text{ m}$ to a position of $(4 \hat{i}+3 \hat{j}+2 \hat{k}) \text{ m}$. The work done by the force on the particle in joules is: (in $\text{ J}$)

$A$ force $F = (5 \hat{i} + 4 \hat{j}) \text{ N}$ acts on a body and produces a displacement $s = (6 \hat{i} - 5 \hat{j} + 3 \hat{k}) \text{ m}$. The work done by the force is: (in $\text{ J}$)

$A$ $50\,kg$ man with a $20\,kg$ load on his head climbs up $20$ steps of $0.25\,m$ height each. The work done in climbing is......$J$

$A$ force of magnitude $30\, N$ acting along $\hat{i} + \hat{j} + \hat{k}$ displaces a particle from point $(2, 4, 1)$ to $(3, 5, 2)$. The work done during this displacement is: