If four charges +12 text{ nC}, -20 text{ nC}, | vedclass

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(B) The side of the square is $a = \sqrt{2} 	ext{ m}$. The diagonal of the square is $d = a\sqrt{2} = \sqrt{2} 	imes \sqrt{2} = 2 	ext{ m}$.The dis

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$81$

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(B) The side of the square is $a = \sqrt{2} 	ext{ m}$. The diagonal of the square is $d = a\sqrt{2} = \sqrt{2} 	imes \sqrt{2} = 2 	ext{ m}$.The distance from the centre of the square to each vertex is $r = d/2 = 2/2 = 1 	ext{ m}$.The electric potential $V$ at the centre due to a point charge $q$ is given by $V = \frac{kq}{r}$,where $k = 9 	imes 10^9 	ext{ N m}^2/	ext{C}^2$.The net potential at the centre is the algebraic sum of the potentials due to individual charges: $V_{net} = \frac{k}{r} (q_1 + q_2 + q_3 + q_4)$.Substituting the given values: $V_{net} = \frac{9 	imes 10^9}{1} 	imes (12 - 20 + 32 - 15) 	imes 10^{-9} 	ext{ V}$.$V_{net} = 9 	imes (9) 	ext{ V} = 81 	ext{ V}$.

If four charges $+12 \text{ nC}, -20 \text{ nC}, +32 \text{ nC}$ and $-15 \text{ nC}$ are arranged at the four vertices of a square of side $\sqrt{2} \text{ m}$,then the net electric potential at the centre of the square due to these four charges is (in $\text{ V}$)

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