If heat is added at constant volume,6300 J o | vedclass

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(B) Heat added at constant volume is equal to the change in internal energy of the system. The change in internal energy is given by $\Delta U = n C_{

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$12600$

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(B) Heat added at constant volume is equal to the change in internal energy of the system. The change in internal energy is given by $\Delta U = n C_{v} \Delta T$.For $\Delta T = 150 \ K$,the change in internal energy is $\Delta U = Q_{v} = 6300 \ J$.Therefore,$6300 = n C_{v} (150) \quad \dots(1)$.We need to find the change in internal energy $\Delta U'$ for $\Delta T' = 300 \ K$.Thus,$\Delta U' = n C_{v} (300) \quad \dots(2)$.Dividing equation $(2)$ by equation $(1)$,we get $\frac{\Delta U'}{6300} = \frac{300}{150} = 2$.Therefore,$\Delta U' = 6300 	imes 2 = 12600 \ J$.

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