If in NH_3 formation N uses its pure atomic o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) If $N$ uses pure atomic orbitals $(2p_x, 2p_y, 2p_z)$ for bonding with $H$ atoms,the three $N-H$ bonds would be formed by the overlap of $N(2p)$ a

Vedclass · Accepted Answer

Molecule will be $T$-shaped

Vedclass · Answer

(D) If $N$ uses pure atomic orbitals $(2p_x, 2p_y, 2p_z)$ for bonding with $H$ atoms,the three $N-H$ bonds would be formed by the overlap of $N(2p)$ and $H(1s)$ orbitals. Since the $p$-orbitals are mutually perpendicular,the bond angles would be $90^{\circ}$. The lone pair would reside in the $2s$ orbital. However,the $N-H$ bonds formed by $p-s$ overlap would have identical strength. The geometry would be pyramidal,not $T$-shaped. Therefore,the statement that the molecule will be $T$-shaped is incorrect.

Column $I$ (Molecules)	Column $II$ (Number of lone pairs on central atom)
$A. \ NH_3$	$1. \ \text{Two}$
$B. \ H_2O$	$2. \ \text{Three}$
$C. \ XeF_2$	$3. \ \text{Zero}$
$D. \ CH_4$	$4. \ \text{Four}$
	$5. \ \text{One}$

If in $NH_3$ formation $N$ uses its pure atomic orbitals,then the wrong statement is:

Similar Questions

Which of the following statement$(s)$ is/are correct?

Species isoelectronic with $BF_3$ would be

The formal charges of $N_{(1)}$,$N_{(2)}$,and $O$ atoms in the structure $N_{(1)} = N_{(2)} = O$ are respectively:

What is an ionic bond? With two suitable examples,explain the difference between an ionic and a covalent bond.

Vedclass Test Series

Exam Paper Generator

Online Exam Module