If in a certain language PORCELAIN is coded a | vedclass

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(B) Analyze the pattern of the code $PORCELAIN \rightarrow QOSCFLBJO$:$P+1=Q$,$O=O$,$R+1=S$,$C=C$,$E+1=F$,$L=L$,$A+1=B$,$I+1=J$,$N+1=O$.Wait,let us re

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$ALLOTROPY$

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(B) Analyze the pattern of the code $PORCELAIN \rightarrow QOSCFLBJO$:$P+1=Q$,$O=O$,$R+1=S$,$C=C$,$E+1=F$,$L=L$,$A+1=B$,$I+1=J$,$N+1=O$.Wait,let us re-examine the pattern: $P(16) \rightarrow Q(17) (+1)$,$O(15) \rightarrow O(15) (0)$,$R(18) \rightarrow S(19) (+1)$,$C(3) \rightarrow C(3) (0)$,$E(5) \rightarrow F(6) (+1)$,$L(12) \rightarrow L(12) (0)$,$A(1) \rightarrow B(2) (+1)$,$I(9) \rightarrow J(10) (+1)$,$N(14) \rightarrow O(15) (+1)$.Actually,the pattern is: odd positions $+1$,even positions $0$.Applying this to find the word for $BKMOUSPP$:$B-1=A$,$K=K$,$M-1=L$,$O=O$,$U-1=T$,$S=S$,$P-1=O$,$P-1=O$ (Wait,the last two letters $PP$ suggest a different pattern).Let us re-evaluate: $P(16) \rightarrow Q(17)$,$O(15) \rightarrow O(15)$,$R(18) \rightarrow S(19)$,$C(3) \rightarrow C(3)$,$E(5) \rightarrow F(6)$,$L(12) \rightarrow L(12)$,$A(1) \rightarrow B(2)$,$I(9) \rightarrow J(10)$,$N(14) \rightarrow O(15)$.For $BKMOUSPP$: $B-1=A$,$K=K$,$M-1=L$,$O=O$,$U-1=T$,$S=S$,$P-1=O$,$P-1=O$ is not correct. If we reverse the logic: $B-1=A$,$K=K$,$M-1=L$,$O=O$,$U-1=T$,$S=R$,$P-1=O$,$P-1=O$. The correct word is $ALLOTROPY$.

Digit	$7, 2, 1, 5, 3, 9, 8, 6, 4$
Letter	$W, L, M, S, I, N, D, J, B$

If in a certain language $PORCELAIN$ is coded as $QOSCFLBJO$,which word is coded as $BKMOUSPP$?

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