If in an examination different weights are assigned to different subjects: Physics $(2)$,Chemistry $(1)$,English $(1)$,and Mathematics $(2)$. If a student scored $60$ in Physics,$70$ in Chemistry,$70$ in English,and $80$ in Mathematics,then his weighted $A.M.$ is:
- A$60$
- B$70$
- C$80$
- DNone of these
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Similar Questions
The median of a set of $19$ observations is $30$. If two observations with values $8$ and $32$ are added,what is the median of the new set of $21$ observations?
Medium
View SolutionConsider a set of observations ${x_1}, {x_2}, {x_3}, ..., {x_{101}}$ such that ${x_1} < {x_2} < {x_3} < ... < {x_{100}} < {x_{101}}$. The mean deviation of this set of observations about a point $k$ is minimum when $k$ equals:
Easy
View SolutionFind the median for the following distribution:
Class Frequency $10-20$ $180$ $20-30$ $82$ $30-40$ $34$ $40-50$ $180$ $50-60$ $136$ $60-70$ $23$ $70-80$ $50$
| Class | Frequency |
| $10-20$ | $180$ |
| $20-30$ | $82$ |
| $30-40$ | $34$ |
| $40-50$ | $180$ |
| $50-60$ | $136$ |
| $60-70$ | $23$ |
| $70-80$ | $50$ |
Medium
View SolutionThe mean of a set of $n$ numbers,when each is divided by $5$,is $\frac{X}{5}$. What is the mean of the original $n$ numbers?
If a variable takes the discrete values $\alpha - 4, \alpha - \frac{7}{2}, \alpha - \frac{5}{2}, \alpha - 3, \alpha - 2, \alpha + \frac{1}{2}, \alpha - \frac{1}{2}, \alpha + 5$ (where $\alpha > 0$),then the median is:
Medium
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