If it was Saturday on 17^{th} December,1982,w | vedclass

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(D) The number of days from $17^{th}$ December $1982$ to $17^{th}$ December $1983$ is $365$ days. Since $365 = 52 	imes 7 + 1$,there is $1$ odd day.

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(D) The number of days from $17^{th}$ December $1982$ to $17^{th}$ December $1983$ is $365$ days. Since $365 = 52 	imes 7 + 1$,there is $1$ odd day. Thus,$17^{th}$ December $1983$ is Saturday $+ 1 = 	ext{Sunday}$.From $17^{th}$ December $1983$ to $17^{th}$ December $1984$,the period includes $1984$ which is a leap year ($366$ days). Since $366 = 52 	imes 7 + 2$,there are $2$ odd days. Thus,$17^{th}$ December $1984$ is Sunday $+ 2 = 	ext{Tuesday}$.Now,we need to find the day for $22^{nd}$ December $1984$. The difference between $17^{th}$ December and $22^{nd}$ December is $22 - 17 = 5$ days.Adding $5$ days to Tuesday: $	ext{Tuesday} + 5 = 	ext{Sunday}$.

If it was Saturday on $17^{th}$ December,$1982$,what will be the day on $22^{nd}$ December,$1984$?

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