If one atom of an element X weighs 6.643 time | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: Calculate the mass of one mole of element $X$ (molar mass).Mass of one atom = $6.643 	imes 10^{-23} \ g$.Molar mass = Mass of one atom

Vedclass · Accepted Answer

$1250$

Vedclass · Answer

(C) Step $1$: Calculate the mass of one mole of element $X$ (molar mass).Mass of one atom = $6.643 	imes 10^{-23} \ g$.Molar mass = Mass of one atom $	imes$ Avogadro's number $(N_A)$.Molar mass = $(6.643 	imes 10^{-23} \ g) 	imes (6.022 	imes 10^{23} \ mol^{-1}) \approx 40 \ g/mol$.Step $2$: Calculate the number of moles in $50 \ kg$ $(50,000 \ g)$.Number of moles = $\frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{50,000 \ g}{40 \ g/mol} = 1250 \ moles$.

If one atom of an element $X$ weighs $6.643 \times 10^{-23} \ g$,then find the number of moles of atoms in $50 \ kg$ of element $X$. (in $moles$)

Similar Questions

Which of the following has the smallest number of molecules $:-$

Two vessels $A$ and $B$ of $1 \, L$ each contain $0.11 \, g$ $CO_2$ gas and $0.07 \, g$ of unknown gas respectively under the same conditions of pressure and temperature. The unknown gas is:

What is the volume occupied by $16 \ g$ methane gas at $STP$ (in $cm^3$)?

$10 \ dm^3$ of $N_2$ gas and $10 \ dm^3$ of gas $X$ at the same temperature and pressure contain the same number of molecules. The gas $X$ is

Mass of $0.1 \ mol$ of methane is (in $g$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module