If only $5 \%$ of the total current is to be passed through a galvanometer of resistance $G$,then the resistance of the shunt will be

  • A
    $\frac{G}{15}$
  • B
    $\frac{G}{17}$
  • C
    $\frac{G}{19}$
  • D
    $\frac{G}{21}$

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Similar Questions

$A$ galvanometer has a $50$ division scale. The battery has no internal resistance. It is found that there is a deflection of $40$ divisions when $R = 2400\,\Omega$. The deflection becomes $20$ divisions when the resistance taken from the resistance box is $4900\,\Omega$. Then we can conclude:

$A$ circuit contains an ammeter,a battery of $30\,V$ and a resistance of $40.8\,\Omega$ all connected in series. If the ammeter has a coil of resistance $480\,\Omega$ and a shunt of $20\,\Omega$,the reading in the ammeter will be .................. $A$.

What is voltage sensitivity? Obtain its equation.

$A$ galvanometer of $25 \,\Omega$ resistance can read a maximum current of $6 \,mA$. It can be used as a voltmeter to measure a maximum of $6 \,V$ by connecting a resistance to the galvanometer. Identify the correct choice in the given answers.

$A$ galvanometer of resistance $50 \Omega$ is connected to a battery of $3 \text{ V}$ along with a resistance of $2950 \Omega$ in series. $A$ full-scale deflection of $30$ divisions is obtained in the galvanometer. In order to reduce this deflection to $20$ divisions,the resistance in series should be: (in $\Omega$)

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