If per H-atom selectivity for chlorination is | vedclass

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Question

(A) The product ratio is calculated as: $(	ext{Number of } H 	ext{ atoms}) 	imes (	ext{Selectivity ratio})$.For Propane $(CH_3-CH_2-CH_3)$:$1^o H

Vedclass · Accepted Answer

Propane + $Cl_2$ / $h
u$ $ightarrow$ $1-$chloropropane : $2-$chloropropane = $6 : 7.6$

Vedclass · Answer

(A) The product ratio is calculated as: $(	ext{Number of } H 	ext{ atoms}) 	imes (	ext{Selectivity ratio})$.For Propane $(CH_3-CH_2-CH_3)$:$1^o H = 6$,$2^o H = 2$.Ratio = $(6 	imes 1) : (2 	imes 3.8) = 6 : 7.6$. Thus,option $A$ is correct.For $2,3-$Dimethylbutane:$1^o H = 12$,$3^o H = 2$.Ratio = $(12 	imes 1) : (2 	imes 5) = 12 : 10 = 6 : 5$. Option $C$ is incorrect.For $2,4-$Dimethylpentane:$1^o H = 12$,$2^o H = 2$,$3^o H = 2$.Ratio = $(12 	imes 1) : (2 	imes 3.8) : (2 	imes 5) = 12 : 7.6 : 10$. Option $D$ is incorrect.

If per $H$-atom selectivity for chlorination is $3^o : 2^o : 1^o = 5 : 3.8 : 1$,then identify the correct product ratio for the following reactions.

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