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Question

(D) The electric field $E$ at a distance $x$ from the centre of a uniformly charged ring of radius $R$ along its axis is given by the formula:$E = \fr

Vedclass · Accepted Answer

Zero

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(D) The electric field $E$ at a distance $x$ from the centre of a uniformly charged ring of radius $R$ along its axis is given by the formula:$E = \frac{kQx}{(R^2 + x^2)^{3/2}}$At the centre of the ring,the distance $x = 0$.Substituting $x = 0$ into the formula,we get:$E_{	ext{centre}} = \frac{kQ(0)}{(R^2 + 0^2)^{3/2}} = 0$Therefore,the electric field at the centre of a uniformly charged ring is always zero,regardless of the potential $V_0$ at the centre.

If the potential at the centre of a uniformly charged ring is $V_0$,then the electric field at its centre will be (assume radius $= R$):

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