If the potential of A is 10,V,then the potent | vedclass

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(B) Let the potential at point $A$ be $V_A = 10\,V$. The battery of $10\,V$ is connected between point $A$ and point $N$. Thus,the potential at point

Vedclass · Accepted Answer

$\frac{50}{3}\,V$

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(B) Let the potential at point $A$ be $V_A = 10\,V$. The battery of $10\,V$ is connected between point $A$ and point $N$. Thus,the potential at point $N$ is $V_N = V_A + 10\,V = 10 + 10 = 20\,V$.The circuit consists of a $1\,\mu F$ capacitor in series with a parallel combination of two $1\,\mu F$ capacitors. The equivalent capacitance of the parallel part is $1\,\mu F + 1\,\mu F = 2\,\mu F$.Now,we have a series circuit with a $2\,\mu F$ capacitor and a $1\,\mu F$ capacitor connected across the potential difference $V_N - V_A = 20 - 10 = 10\,V$.The potential difference across the capacitors is inversely proportional to their capacitance. Let $V_B$ be the potential at $B$. The potential difference across the $1\,\mu F$ capacitor (between $B$ and $A$) is $V_B - V_A = V_{total} 	imes \frac{C_{eq}}{C_{branch}} = 10 	imes \frac{2}{2+1} = 10 	imes \frac{2}{3} = \frac{20}{3}\,V$.Therefore,$V_B = V_A + \frac{20}{3} = 10 + \frac{20}{3} = \frac{30+20}{3} = \frac{50}{3}\,V$.

If the potential of $A$ is $10\,V$,then the potential of $B$ is

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