If pure unhybridised orbitals are used in for | vedclass

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(C) In $CH_4$,if we use pure unhybridised orbitals,the $3$ $p$-orbitals of carbon $(p_x, p_y, p_z)$ would overlap with $1s$ orbitals of $3$ hydrogen a

Vedclass · Accepted Answer

Geometry will be tetrahedral.

Vedclass · Answer

(C) In $CH_4$,if we use pure unhybridised orbitals,the $3$ $p$-orbitals of carbon $(p_x, p_y, p_z)$ would overlap with $1s$ orbitals of $3$ hydrogen atoms at $90^o$ angles.The $4^{th}$ hydrogen atom would overlap with the $2s$ orbital of carbon.Since $p$-orbitals are directional and $s$-orbitals are spherical,the bond lengths and bond angles would not be equivalent to the observed tetrahedral geometry.Specifically,the geometry would not be tetrahedral,as the $3$ $p$-bonds would be at $90^o$ to each other,and the $4^{th}$ bond would be different in nature.Therefore,the statement that the geometry will be tetrahedral is incorrect.

If pure unhybridised orbitals are used in forming $CH_4$ then which statement is incorrect :-

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