If the adsorbate is held on a surface by weak Van der Waals forces,the adsorption process is called:

The plot of $\log(\frac{x}{m})$ against $\log P$ is a straight line inclined at an angle of $45^{\circ}$. When the pressure is $0.5 \ atm$ and the Freundlich parameter $(K)$ is $10$,the amount of solute adsorbed per gram of adsorbent will be $(\log 5 = 0.699)$ .......... $g$.

Assertion $(A)$: van der Waals' forces are responsible for chemisorption.
Reason $(R)$: High temperature is favourable for chemisorption.
The correct answer is

Freundlich adsorption isotherms for the physical adsorption of a gas at temperatures $T_1$,$T_2$ and $T_3$ are shown in the graph given below. The correct relationship between $T_1$,$T_2$ and $T_3$ is:

If the value of $\frac{1}{n}$ is equal to $1$ in the Freundlich adsorption isotherm, then $\frac{x}{m} = $ (where $x = $ mass of adsorbate, $m = $ mass of the adsorbent, $p = $ pressure of the gas).

Assertion : Physical adsorption of molecules takes place on the surface only.
Reason : In this process,the bonds of the adsorbed molecules are broken.