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(C) Given the ratio of amplitudes of two sources is $\frac{a_1}{a_2} = \frac{3}{5}$.The intensity $I$ is proportional to the square of the amplitude,$

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$16:1$

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(C) Given the ratio of amplitudes of two sources is $\frac{a_1}{a_2} = \frac{3}{5}$.The intensity $I$ is proportional to the square of the amplitude,$I \propto a^2$.The ratio of maximum intensity to minimum intensity in an interference pattern is given by the formula:$\frac{I_{\max}}{I_{\min}} = \frac{(a_1 + a_2)^2}{(a_1 - a_2)^2}$.Substituting the given values:$\frac{I_{\max}}{I_{\min}} = \frac{(3 + 5)^2}{(3 - 5)^2} = \frac{8^2}{(-2)^2} = \frac{64}{4} = \frac{16}{1}$.Therefore,the ratio of intensities at maxima and minima is $16:1$.

If the amplitude ratio of two sources producing interference is $3:5$,the ratio of intensities at maxima and minima is

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