If the angle $\theta$ between the line $\frac{x+1}{1}=\frac{y-1}{2}=\frac{z-2}{2}$ and the plane $2x-y+\sqrt{\lambda}z+4=0$ is such that $\sin \theta=\frac{1}{3}$,then $\lambda+1=$

  • A
    $\frac{5}{3}$
  • B
    $\frac{-5}{3}$
  • C
    $\frac{8}{3}$
  • D
    $\frac{-8}{3}$

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