If the angle of minimum deviation produced by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an equilateral prism, the angle of the prism $A = 60^{\circ}$.Given that the angle of minimum deviation $\delta_m = A = 60^{\circ}$.The formul

Vedclass · Accepted Answer

$1.732$

Vedclass · Answer

(C) For an equilateral prism, the angle of the prism $A = 60^{\circ}$.Given that the angle of minimum deviation $\delta_m = A = 60^{\circ}$.The formula for the refractive index $n$ of a prism is given by $n = \frac{\sin((A + \delta_m) / 2)}{\sin(A / 2)}$.Substituting the values, we get $n = \frac{\sin((60^{\circ} + 60^{\circ}) / 2)}{\sin(60^{\circ} / 2)}$.$n = \frac{\sin(120^{\circ} / 2)}{\sin(30^{\circ})} = \frac{\sin(60^{\circ})}{\sin(30^{\circ})}$.Since $\sin(60^{\circ}) = \frac{\sqrt{3}}{2}$ and $\sin(30^{\circ}) = \frac{1}{2}$, we have $n = \frac{\sqrt{3} / 2}{1 / 2} = \sqrt{3}$.The value of $\sqrt{3}$ is approximately $1.732$.

If the angle of minimum deviation produced by an equilateral prism is equal to the angle of the prism, then the refractive index of the material of the prism is nearly

Similar Questions

$A$ prism is made of glass having a refractive index of $\sqrt{2}$. If the angle of minimum deviation is equal to the angle of the prism, then the angle of the prism is: (in $^{\circ}$)

The cross-section of a prism $(\mu = 1.5)$ is an equilateral triangle. $A$ ray of light is incident perpendicular on one of the faces. The angle of deviation of the ray is......$^o$

$A$ thin prism $P_1$ with angle $4^o$ and made from glass of refractive index $1.54$ is combined with another thin prism $P_2$ made from glass of refractive index $1.72$ to produce dispersion without deviation. The angle of prism $P_2$ is......$^o$

If a thin prism of glass is dipped into water,then the minimum deviation (with respect to air) of light produced by the prism will be: $\left( {_a{\mu _g} = \frac{3}{2} \text{ and } _a{\mu _w} = \frac{4}{3}} \right)$

$A$ glass prism $A$ deviates the red and blue rays through $10^{\circ}$ and $12^{\circ}$ respectively. $A$ second prism $B$ deviates them through $8^{\circ}$ and $10^{\circ}$ respectively. The ratio of their dispersive powers is ($A$ to $B$):

Vedclass Test Series

Exam Paper Generator

Online Exam Module