If the angles of dip at two places are 30^o a | vedclass

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(A) The horizontal component of the Earth's magnetic field $(B_H)$ is given by the formula $B_H = B \cos \phi$,where $B$ is the total magnetic field a

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$\sqrt{3} : \sqrt{2}$

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(A) The horizontal component of the Earth's magnetic field $(B_H)$ is given by the formula $B_H = B \cos \phi$,where $B$ is the total magnetic field and $\phi$ is the angle of dip.Assuming the total magnetic field $B$ is the same at both locations:For the first place,$(B_H)_1 = B \cos 30^o = B \frac{\sqrt{3}}{2}$.For the second place,$(B_H)_2 = B \cos 45^o = B \frac{1}{\sqrt{2}}$.The ratio of the horizontal components is $\frac{(B_H)_1}{(B_H)_2} = \frac{B \cos 30^o}{B \cos 45^o} = \frac{\sqrt{3}/2}{1/\sqrt{2}} = \frac{\sqrt{3}}{2} 	imes \sqrt{2} = \frac{\sqrt{3}}{\sqrt{2}}$.Thus,the ratio is $\sqrt{3} : \sqrt{2}$.

If the angles of dip at two places are $30^o$ and $45^o$ respectively,then the ratio of horizontal components of earth's magnetic field at the two places will be

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