If the angular speed of the earth is doubled, | vedclass

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(C) The acceleration due to gravity $(g)$ at any point on the surface of the earth is given by the formula $g' = g - \omega^2 R \cos^2 \lambda$,where

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Remains same

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(C) The acceleration due to gravity $(g)$ at any point on the surface of the earth is given by the formula $g' = g - \omega^2 R \cos^2 \lambda$,where $\omega$ is the angular speed of the earth,$R$ is the radius of the earth,and $\lambda$ is the latitude.At the north pole,the latitude $\lambda = 90^\circ$.Since $\cos(90^\circ) = 0$,the expression becomes $g' = g - \omega^2 R (0)^2 = g$.Therefore,the acceleration due to gravity at the poles is independent of the angular speed of the earth $(\omega)$.Thus,if the angular speed is doubled,the value of $g$ at the north pole remains the same.

If the angular speed of the earth is doubled,the value of acceleration due to gravity $(g)$ at the north pole:

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