If the area of a square is increased by 44 %, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the initial side of the square be $s_1 = 10 	ext{ cm}$.Therefore,the initial area of the square is $A_1 = (s_1)^2 = 10^2 = 100 	ext{ cm}^2$.

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(D) Let the initial side of the square be $s_1 = 10 	ext{ cm}$.Therefore,the initial area of the square is $A_1 = (s_1)^2 = 10^2 = 100 	ext{ cm}^2$.Given that the area increases by $44 \%$,the new area $A_2$ is:$A_2 = A_1 + 44\% 	ext{ of } A_1 = 100 + 44 = 144 	ext{ cm}^2$.Let the new side of the square be $s_2$. Since $A_2 = (s_2)^2$,we have:$s_2 = \sqrt{144} = 12 	ext{ cm}$.The percentage increase in the side is calculated as:$	ext{Percentage increase} = \frac{s_2 - s_1}{s_1} 	imes 100 = \frac{12 - 10}{10} 	imes 100 = \frac{2}{10} 	imes 100 = 20 \%$.Thus,each side increases by $20 \%$.

If the area of a square is increased by $44 \%$,while retaining its shape as a square,by what percentage does each of its sides increase?

Similar Questions

The volume of a cube is $216 \, cm^3$. Part of this cube is then melted to form a cylinder of length $8 \, cm$. Find the volume of the cylinder (in $cm^3$)?

$A$ rectangular paper,when folded into two congruent parts,has a perimeter of $34\, cm$ for each part when folded along one set of sides and a perimeter of $38\, cm$ when folded along the other set of sides. What is the area of the original paper in $cm^2$?

In the figure,$DE \parallel BC$. If $DE = 3 \text{ cm}$,$BC = 6 \text{ cm}$,and the area of $\Delta ADE = 15 \text{ cm}^2$,then the area of $\Delta ABC$ is ............ $\text{cm}^2$.

If the ratio of areas of two circles is $4:9,$ then the ratio of their circumferences will be

The area of a ring whose outer and inner radii are respectively $20 \, cm$ and $15 \, cm$ is? (in $cm^2$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module