If the Cartesian coordinates of a point are $\left(\frac{-5 \sqrt{3}}{2}, \frac{5}{2}\right)$,then its polar coordinates are

The point of intersection of the diagonals of a square is at the origin,and the coordinate axes are drawn along the diagonals. If the side length of the square is $a$,then which of the following is $NOT$ a vertex of the square?

If a square $ABCD$,where $A(0,0), B(2,0), C(2,2)$ and $D(0,2)$ undergoes the following transformations successively,then the final figure would be a:
$(i)$ $f_1(x, y) \longrightarrow (y, x)$
(ii) $f_2(x, y) \longrightarrow (x+3y, y)$
(iii) $f_3(x, y) \longrightarrow \left(\frac{x-y}{2}, \frac{x+y}{2}\right)$

The Cartesian coordinates of the point whose polar coordinates are $\left(\frac{1}{2}, 120^{\circ}\right)$ are:

The points $(-a, -b)$,$(0, 0)$,$(a, b)$,and $(a^2, ab)$ are

If the polar coordinates of a point are $\left( \sqrt{2}, -\frac{3\pi}{4} \right)$,what are its Cartesian coordinates?