If the chord through the points whose eccentric angles are $\theta$ and $\phi$ on the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ passes through the focus,then the value of $(1 + e) \tan(\frac{\theta}{2}) \tan(\frac{\phi}{2})$ is

  • A
    $e + 1$
  • B
    $e - 1$
  • C
    $1 - e$
  • D
    $0$

Explore More

Similar Questions

Find the equation of the ellipse with its center at the origin,passing through the points $(-3, 1)$ and $(2, -2)$,given that $a > b$.

The tangent to the ellipse $9x^2 + 16y^2 = 288$ making equal intercepts on the coordinate axes intersects the $X$-axis and the $Y$-axis at points $A$ and $B$ respectively. Then,the area of $\triangle OAB$ (where $O$ is the origin) is:

For the ellipse given by $\frac{(x-3)^2}{25}+\frac{(y-2)^2}{16}=1$,match the equations of the lines given in List-$I$ with those on the List-$II$.
List-$I$ List-$II$
$(i)$ The equation of the major axis $(p)$ $3x = 34$
$(ii)$ The equation of a directrix $(q)$ $y = 2$
$(iii)$ The equation of a latus rectum $(r)$ $x + y = 9$
$(s)$ $x = 6$
$(t)$ $x = 3$
$(u)$ $3y = 34$

If the radius of the largest circle with centre $(2,0)$ inscribed in the ellipse $x^2+4y^2=36$ is $r$,then $12r^2$ is equal to

The parametric equations of the ellipse whose foci are $(-3, 0)$ and $(9, 0)$ and eccentricity is $\frac{1}{3}$,are

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo