If the concentration of CrO_4^{2-} ions in a | vedclass

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(D) The dissociation of silver chromate $(Ag_2CrO_4)$ is given by: $Ag_2CrO_4(s) \rightleftharpoons 2Ag^+(aq) + CrO_4^{2-}(aq)$.Given that the concent

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$32 	imes 10^{-12}$

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(D) The dissociation of silver chromate $(Ag_2CrO_4)$ is given by: $Ag_2CrO_4(s) ightleftharpoons 2Ag^+(aq) + CrO_4^{2-}(aq)$.Given that the concentration of $[CrO_4^{2-}] = 2 	imes 10^{-4} \ M$.According to the stoichiometry,$[Ag^+] = 2 	imes [CrO_4^{2-}] = 2 	imes (2 	imes 10^{-4} \ M) = 4 	imes 10^{-4} \ M$.The solubility product expression is $K_{sp} = [Ag^+]^2 [CrO_4^{2-}]$.Substituting the values: $K_{sp} = (4 	imes 10^{-4})^2 	imes (2 	imes 10^{-4}) = (16 	imes 10^{-8}) 	imes (2 	imes 10^{-4}) = 32 	imes 10^{-12}$.

If the concentration of $CrO_4^{2-}$ ions in a saturated solution of silver chromate is $2 \times 10^{-4} \ M$,the solubility product of silver chromate will be:

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