If the conductivity of mercury at 0^{circ} , | vedclass

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(C) Given: Conductivity $\kappa = 1.07 	imes 10^{6} \, S \, m^{-1}$ and Resistance $R = 0.243 \, \Omega$. The relationship between conductivity $(\ka

Vedclass · Accepted Answer

$26$

Vedclass · Answer

(C) Given: Conductivity $\kappa = 1.07 	imes 10^{6} \, S \, m^{-1}$ and Resistance $R = 0.243 \, \Omega$. The relationship between conductivity $(\kappa)$,conductance $(G)$,and cell constant $(G^{*})$ is $\kappa = G 	imes G^{*}$. Since $G = \frac{1}{R}$,we have $\kappa = \frac{1}{R} 	imes G^{*}$. Rearranging for the cell constant: $G^{*} = \kappa 	imes R$. Substituting the values: $G^{*} = (1.07 	imes 10^{6} \, S \, m^{-1}) 	imes (0.243 \, \Omega) = 0.26001 	imes 10^{6} \, m^{-1}$. Expressing in the form $x 	imes 10^{4} \, m^{-1}$: $G^{*} = 26.001 	imes 10^{4} \, m^{-1}$. Therefore,the value of $x$ is $26$.

If the conductivity of mercury at $0^{\circ} \, C$ is $1.07 \times 10^{6} \, S \, m^{-1}$ and the resistance of a cell containing mercury is $0.243 \, \Omega$,then the cell constant of the cell is $x \times 10^{4} \, m^{-1}$. The value of $x$ is ...... (Nearest integer).

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