If the crystal field splitting energy of a tetrahedral complex $\Delta_t$ of the type $[ML_4]^{n+}$ is $x \ eV$,what is the crystal field splitting energy with respect to an octahedral complex,$[ML_6]^{n+}$?

  • A
    $\frac{9x}{4} \ eV$
  • B
    $\frac{9x}{8} \ eV$
  • C
    $\frac{4x}{9} \ eV$
  • D
    $\frac{4x}{5} \ eV$

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Similar Questions

The crystal field stabilization energy for a high spin $d^4$ octahedral complex is:

Match List-$I$ with List-$II$. Choose the correct answer from the options given below:
| List-$I$ (Complex ion) | List-$II$ (Electronic Configuration) |
| :--- | :--- |
| $A. [Cr(H_2O)_6]^{3+}$ | $I. t_{2g}^2 e_g^0$ |
| $B. [Fe(H_2O)_6]^{3+}$ | $II. t_{2g}^3 e_g^0$ |
| $C. [Ni(H_2O)_6]^{2+}$ | $III. t_{2g}^3 e_g^2$ |
| $D. [V(H_2O)_6]^{3+}$ | $IV. t_{2g}^6 e_g^2$ |

$\left[ Ti \left( H_{2} O \right)_{6} \right]^{3+}$ absorbs light of wavelength $498 \, nm$ during a $d-d$ transition. The octahedral splitting energy for the above complex is $....... \times 10^{-19} \, J$. (Round off to the Nearest Integer). Given: $h = 6.626 \times 10^{-34} \, Js$,$c = 3 \times 10^{8} \, ms^{-1}$.

The complex ion that will lose its crystal field stabilization energy upon oxidation of its metal to $+3$ state is

The degeneracy of $d-$orbitals is lost under:
$I$. Strong field ligand
$II$. Weak field ligand
$III$. Mixed field ligand
$IV$. Chelated ligand field
Choose the correct code:

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