If the diameter of a carbon atom is $0.15 \,nm$,calculate the number of carbon atoms which can be placed side by side in a straight line across the length of a scale of length $20 \,cm$.

  • A
    $1.33 \times 10^9$
  • B
    $1.33 \times 10^8$
  • C
    $1.33 \times 10^{10}$
  • D
    $1.33 \times 10^7$

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